Answer
See answers.
Work Step by Step
a. The clockwise current in the left-hand loop. By the right hand rule, it produces a magnetic field that is into the page within the loop, and out of the page outside the loop.
The other loop is in a magnetic field that is directed out of the page. While the switch S is closing, before the current reaches its steady state value, the right hand loop experiences more and more field lines pointing out of the page. There will be an induced current that will produce a magnetic field into the page, to oppose the change in flux. By the right hand rule, the induced current is clockwise.
b. After a long time, the current in the left-hand loop is constant, and the field is steady in the right-hand loop. There is no change in flux, so there is no induced current in the right-hand coil.
c. While the right-hand loop is being pulled to the right, it experiences less and less field lines pointing out of the page. There will be an induced current that will produce a magnetic field out of the page, to oppose the change in flux. By the right hand rule, the induced current is counterclockwise.
d. After a long time, the current in the left-hand loop is constant, and the field is steady in the right-hand loop. There is no change in flux, so whether a switch in the right-hand loop is closed doesn’t matter; there is no induced current in the right-hand coil.
