## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

$v = 110~km/h$
We know that; $KE = \frac{1}{2}mv^2$ We can equate the kinetic energy of the car and the kinetic energy of the truck to find the required speed of the car: $KE_{car} = KE_{truck}$ $\frac{1}{2}(1000~kg)v^2= \frac{1}{2}(20,000~kg)(25~km/h)^2$ $v^2 = (20)(25~km/h)^2$ $v = \sqrt{(20)(25~km/h)^2}$ $v = 110~km/h$