#### Answer

During the interval AB, the work done on the object is -4 J
During the interval BC, the work done on the object is 0
During the interval CD, the work done on the object is 2 J
During the interval DE, the work done on the object is 2 J

#### Work Step by Step

The work done on the object is equal to the change in kinetic energy of the object.
We can find the work done on the object during the interval AB.
$W = \Delta KE$
$W = -4~J$
We can find the work done on the object during the interval BC.
$W = \Delta KE$
$W = 0~J$
We can find the work done on the object during the interval CD.
$W = \Delta KE$
$W = 2~J$
We can find the work done on the object during the interval DE.
$W = \Delta KE$
$W = 2~J$