Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 4 - Kinematics in Two Dimensions - Exercises and Problems: 70

Answer

(a) $\alpha = 4.0~rad/s^2$ (b) $a = 0.12~m/s^2$

Work Step by Step

(a) $\omega = (2.0+\frac{1}{2}t^2)~rad/s$ $\alpha = \frac{d\omega}{dt}$ $\alpha = (t)~rad/s^2$ We can find the angular acceleration at t = 4.0 s: $\alpha = (4.0)~rad/s^2$ $\alpha = 4.0~rad/s^2$ (b) We can find the tangential acceleration of a tooth on the gear. $a = \alpha ~r$ $a = (4.0~rad/s^2)(0.030~m)$ $a = 0.12~m/s^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.