## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

(a) $v = 418~m/s$ (b) $v = 197~m/s$
We can find the angular speed of the earth as it rotates once each day: $\omega = \frac{2\pi~rad}{(24)(3600~s)}$ $\omega = 7.27\times 10^{-5}~rad/s$ Note that for a point on the earth's surface at a latitude of $\theta$, the radius of rotation is $(6.4\times 10^6~m)~cos(\theta)$ (a) $v = \omega ~r$ $v = (7.27\times 10^{-5}~rad/s)(6.4\times 10^6~m)~cos(26^{\circ})$ $v = 418~m/s$ (b) $v = \omega ~r$ $v = (7.27\times 10^{-5}~rad/s)(6.4\times 10^6~m)~cos(65^{\circ})$ $v = 197~m/s$