Answer
$C = 2.0\times 10^{-10}~F$
Work Step by Step
We can find the capacitance:
$C = \frac{Q}{\Delta V}$
$C = \frac{20\times 10^{-9}~C}{100~V}$
$C = 2.0\times 10^{-10}~F$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0321740904
ISBN 13:
978-0-32174-090-8
Chapter 29 - Potential and Field - Exercises and Problems - Page 863: 24
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