Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 29 - Potential and Field - Exercises and Problems - Page 863: 19

Answer

The battery voltage is $3.0~V$

Work Step by Step

We can find the battery voltage: $\Delta V = \frac{Q}{C}$ $\Delta V = \frac{30\times 10^{-6}~C}{10\times 10^{-6}~F}$ $\Delta V = 3.0~V$ The battery voltage is $3.0~V$
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