Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 23 - Ray Optics - Exercises and Problems - Page 689: 20

Answer

$\Delta\theta =0.4^{\circ}$

Work Step by Step

Model: Use the ray model of light Visualize: Using Snell’s law, $n_{air}\ sin30^{\circ} = n_{red}\sin\theta_{red}$ $\Rightarrow \theta_{red}= sin^{-1}(\frac{sin30^{\circ}}{1.52}) = 19.2^{\circ}$ $n_{air}\ sin30^{\circ} = n_{violet} \ sin\theta_{violet}$ $\Rightarrow \theta_{violet}= sin^{-1}(\frac{sin30^{\circ}}{1.55}) = 18.8^{\circ}$ Thus the angular spread is: $\Delta\theta=\theta_{red}-\theta_{violet} =19.2^{\circ}-18.8^{\circ}=0.4^{\circ}$
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