Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 23 - Ray Optics - Exercises and Problems - Page 689: 2

Answer

The aperture width is $~~8.0~cm$

Work Step by Step

We can use similar triangles to find the aperture width $w$: $\frac{w}{2.00~m} = \frac{12.0~cm}{3.00~m}$ $w = \frac{(2.00~m)(12.0~cm)}{3.00~m}$ $w = 8.0~cm$ The aperture width is $~~8.0~cm$
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