Answer
89 m
Work Step by Step
It is given that:
time delay for spectator A is 0.23 s
time delay for spectator B is 0.12 s
velocity of sound in air v = 343 m/s
So, Distance for spectator A is
$d_A = v\Delta t_A =(343\ m/s)(0.23 s) = 78.89\ m = 79\ m$
Distance for spectator B is
$d_B = v\Delta t_B =(343\ m/s)(0.12 s) = 41.16\ m = 41\ m$
Therefore;
$D=\sqrt (d_A^2+d_B^2) = \sqrt (79^2+41^2) = 89\ m$
