Answer
$\lambda=0.333mm$
Work Step by Step
As we know that
$v=f\lambda$
$\lambda=\frac{v}{f}$
We plug in the known values to obtain:
$\lambda=\frac{1500}{4.50\times 10^6}=3.33\times 10^{-4}=0.333\times 10^{-3}=0.333mm$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 17 - Waves-II - Problems - Page 506: 11b
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