Answer
The product can be formed using $Cl_2$ and $H_2O$
Work Step by Step
The $Cl_2$ forms a chloronium ion. This ion is then opened up by the attack of $H_2O$. This adds the Chlorine and OH anti to each other.
Organic Chemistry (8th Edition)
by Wade Jr., L. G.
Published by
Pearson
ISBN 10:
0321768418
ISBN 13:
978-0-32176-841-4
Chapter 8 - Reactions of Alkenes - Study Problems - Page 389: 8-59 d
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