Answer
The product can be formed using (1) $Hg(OAc)_2$, $CH_3OH$ and (2) $NaBH_4$.
Work Step by Step
$Hg(OAc)_2$ and $CH_3OH$ adds $CH_3O$ on the most substituted carbon and $Hg(OAc)_2$ on the least substituted carbon. Then $Hg(OAc)_2$ is replaced by H using $NaBH_4$.