Organic Chemistry (8th Edition)

Published by Pearson
ISBN 10: 0321768418
ISBN 13: 978-0-32176-841-4

Chapter 8 - Reactions of Alkenes - Study Problems - Page 389: 8-59 f

Answer

The product can be formed using (1) $Hg(OAc)_2$, $CH_3OH$ and (2) $NaBH_4$.

Work Step by Step

$Hg(OAc)_2$ and $CH_3OH$ adds $CH_3O$ on the most substituted carbon and $Hg(OAc)_2$ on the least substituted carbon. Then $Hg(OAc)_2$ is replaced by H using $NaBH_4$.
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