Answer
The alcohol is of $2^{\circ}$. he IUPAC name of the compound is $cis-4−chlorocyclohex-2-en−1−ol$
Work Step by Step
The compound has 8 carbon atoms in its longest ring. It has a chloro at position 4, a double bond at position 2 and the alcohol group at position 1. The carbon having the alcohol group is connected to two other carbon atoms, so the alcohol is of $2^{\circ}$. It has the $cis$ configuration. The IUPAC name of the compound is $cis-4−chlorocyclohex-2-en−1−ol$
