Answer
The alcohol is of $1^{\circ}$. It has the $E$ configuration. The IUPAC name of the compound is $(E)-4,5−dimethylhex-3-en−1−ol$
Work Step by Step
The compound has 6 carbon atoms in its longest chain. It has 2 methyl at positions 4 and 5, a double bond at position 3 and the alcohol group at position 1. The carbon having the alcohol group is connected to 1 other carbon atom, so the alcohol is of $1^{\circ}$. It has the $E$ configuration. The IUPAC name of the compound is $(E)-4,5−dimethylhex-3-en−1−ol$
