Answer
a. 107.87 amu
b. 48.16%
c. 108.9 amu
Work Step by Step
a. Looking at the periodic table, atomic number of silver is 107.87 amu
b. Abundance I_{2}= 100% - abundance I_{1} = 100% - 51.84% = 48.16%
c. Atomic mass = (mass I1)(Abundance I1)+(mass I2)(abundance I2)
So, mass I2 = \frac{Atomic mass - (mass I1)(Abundance I1)}{Abundance I2}
= \frac{107.87-(106.905)(0.5184}{0.4816}
=108.9 amu (4 sigfigs)
