Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 4 - Atoms and Elements - Exercises - Problems - Page 125: 102

Answer

64.91 amu

Work Step by Step

Atomic mass = (mass I1)(Abundance I1)+(mass I2)(abundance I2) So, mass I2 = \frac{Atomic mass - (mass I1)(Abundance I1)}{Abundance I2} =\frac{63.546-(62.939\times0.6917)}{1-0.6917} = 64.91 amu
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