Answer
6.717 x $10^{-13}$ %
Work Step by Step
The volume of a sphere is $\frac{4\pi{r^{3}}}{3}$
In the hydrogen nucleus, there is only one proton, so the nucleus radius will be equal with the proton radius => V $\approx$ 4.1888 $fm^{3}$
$V_{atom}$ = 623614.5193 $pm^{3}$
1 pm = 1000 fm => 1 $pm^{3}$ = $10^{9} fm^{3}$
$V_{atom}$ = 623614.5193 * $10^{9} fm^{3}$
$V_{nucleus}$ = 4.1888 $fm^{3}$
$\frac{p}{100}$ * $V_{atom}$ = $V_{nucleus}$
p = $\frac{V_{nucleus}*100}{V_{atom}}$
p = $\frac{4.1888 fm^{3}*100}{623614.5193 * 10^{9} fm^{3}}$
p = 6.717 x $10^{-13}$ %
