Answer
2.4875 x $10^{18}$ protons
Work Step by Step
398 mC = 398 x $10^{-3}$ C
1 proton.........1.6 x $10^{-19}$ C
n protons.........398 x $10^{-3}$ C
n = $\frac{398 x 10^{-3} C}{1.6 x 10^{-19} C}$ = 2.4875 x $10^{18}$ protons
Introductory Chemistry (5th Edition)
by Tro, Nivaldo J.
Published by
Pearson
ISBN 10:
032191029X
ISBN 13:
978-0-32191-029-5
Chapter 4 - Atoms and Elements - Exercises - Cumulative Problems - Page 125: 104
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