Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 3 - Matter and Energy - Exercises - Problems - Page 89: 67

Answer

$-62.22^{\circ}C$ $211 K$

Work Step by Step

Use the formula $(^{\circ}F - 32)\times\frac{5}{9}$ to convert from Fahrenheit to Celsius and simply add 273.15 to the Celsius to convert to Kelvin: $(-80^{\circ}F - 32 )\times \frac{5}{9} = -62.22^{\circ}C$ $(-80^{\circ}F - 32 )\times \frac{5}{9} + 273.15 K= 211.928 K$
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