Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 3 - Matter and Energy - Exercises - Problems - Page 89: 69

Answer

$-173.2^{\circ}F$ $159.15 K$

Work Step by Step

Use the formula $(∘C\times\frac{9}{5})+32$ to convert from Celsius to Fahrenheit and to convert from Celcius to Kelvin, simply add 273.15 to the Celsius temperature. $(-114∘C\times\frac{9}{5})+32 = -173.2^{\circ}F$ $(-114∘C +273.15K)=159.15$
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