Answer
Please see the work below.
Work Step by Step
We know that the first equation is given as
$\frac{1}{4}P_4O_{10}+\frac{3}{2}H_2O\rightarrow H_3PO_4(aq)\space \Delta H=-96.2KJ$
The second equation is given as
$P_4O_{10}+6H_2O(l)\rightarrow 4H_3PO_4(aq)$
