Answer
Please see the work below.
Work Step by Step
We know that
$\frac{-1267KJ}{4mol\space NH_3}\times \frac{1mol\space NH_3}{17.03g}=-18.60\frac{KJ}{g}$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 6 - Thermochemistry - Questions and Problems - Page 261: 6.65
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