Answer
Please see the work below.
Work Step by Step
We know that
$0.1068\times \frac{1mol\space H_2}{2.016g\space H_2}\times\frac{2mol\space Al}{3mol\space H_2}=0.0353174mol\space Al$
$\%Al=\frac{0.0353174mol\space Al\times 26.98}{1.118}\times 100\%=85.229\%$