Answer
Please see the work below.
Work Step by Step
We know that
$molarity=\frac{moles \space of\space solute }{Liters \space of \space solution}$
$molartiy=\frac{0.024502\space mol\space Na_2SO_4 }{0.0250L}=0.9801M$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 4 - Chemical Reactions - Questions and Problems - Page 177: 4.152
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