Answer
$80.063 amu$
$98.064amu$
Work Step by Step
We can find the formula mass of $SO_3$ as
$32.066+3\times 15.999amu=80.063 amu$
We can find the formula mass of $H_2SO_4$ as
$2\times 1.001+32.066+4\times 15.999=98.064amu$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 3 - Calculations with Chemical Formulas and Equations - Exercises - Page 91: 3.2
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