General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 3 - Calculations with Chemical Formulas and Equations - Exercises - Page 90: 3.1

Answer

a. formula mass for N$O_{2}$ is 46 amu. b. formula mass for glucose $C_{6}$$H_{12}$$O_{6}$ is 180 amu. c. FM of NaOH is 40 amu d. FM of Mg$(OH)_{2}$ = 58 amu

Work Step by Step

a. formula mass for N$O_{2}$. FM of N$O_{2}$ is the sum of atomic masses of all atoms in formula: 1 x AM of N = 14.0 amu 2 x AM of O = 2 x 16.0 = 32.0 amu __________________________ FM = 14.0 amu + 32.0 amu = 46.0 amu FM of N$O_{2}$ is 46 amu. b. formula mass for glucose $C_{6}$$H_{12}$$O_{6}$. FM of $C_{6}$$H_{12}$$O_{6}$ is the sum of atomic masses of all atoms in formula: 6 x AM of C = 6 x 12.0 amu = 72.0 amu 12 x AM of H= 12 x 1.0 amu = 12.0 amu 6 x AM of O = 6 x 16.0 amu = 96.0 amu _______________________________________ FM of $C_{6}$$H_{12}$$O_{6}$ = 72.0 amu + 12.0 amu + 96.0 amu FM of $C_{6}$$H_{12}$$O_{6}$ = 180.0 amu FM of $C_{6}$$H_{12}$$O_{6}$ = 180 amu. c. formula mass for sodium hydroxide NaOH. 1 x AM of Na = 1 x 23.0 amu = 23.0 amu 1 x AM of O = 1 x 16.0 amu =16.0 amu 1 X AM of H = 1 x 1.0 amu = 1.0 amu ---------------------------------------- FM of NaOH = 23.0 amu + 16.o amu + 1.0 amu FM of NaOH is 40 amu d. Formula mass Mg$(OH)_{2}$ 1 x AM of Mg = 1 x 24.3 amu = 24.3 amu 2 X AM of O= 2 x 16.0 amu = 32.0 amu 2 x AM of H = 2 x 1.0 amu = 2 amu ___________________________ FM of Mg$(OH)_{2}$ = 24.3 amu + 32.0 amu + 2.0 amu FM of Mg$(OH)_{2}$ = 58.3 amu FM of Mg$(OH)_{2}$ = 58 amu
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