Chapter 3 - Calculations with Chemical Formulas and Equations - Exercises - Page 122: 3.95

Please see the work below.

We know that $4.15g\space TiO_2\times \frac{1 mol \space TiO_2}{79.9g \space TiO_2}\times \frac{3 \space mol \space TiCl_4}{3 mol \space TiO_2}\times \frac{189.7g}{1mol\space TiCl_4}=9.85g\space TiCl_4$ $5.67g\space C\times \frac{1 mol}{12.0g }\times \frac{3 \space mol \space TiCl_4}{4 mol \space C}\times \frac{189.7g}{1mol\space TiCl_4}=67.2g\space TiCl_4$