Answer
K$O_{2}$ gives the smallest amount of oxygen, so this substance is the limiting reactant. The amount of oxygen that can be obtained is 0.19 mol.
Work Step by Step
Strategy: Find how many moles oxygen yield the given moles of each reactant.
The one reactant that yields the smaller amount of product is the limiting reactant.
4 K$O_{2}$ (s) + 2$H_{2}$O (l) ${\longrightarrow}$ 4 KOH (s) + 3 $O_{2}$ (g)
Step 1:
0.25 mol K$O_{2}$ x $\frac{3 mol(O_{2})}{4 mol(KO_{2})}$= 0.19 mol $O_{2}$
0.15 mol $H_{2}$O x $\frac{3 mol(O_{2})}{2 mol(H_{2}O)}$ = 0.225 mol $O_{2}$
0.25 mol K$O_{2}$ gives the smallest amount of oxygen, so this substance is the limiting reactant. The amount of oxygen that can be obtained is 0.19 mol.
