Answer
$159.10 kJ/mol$
Work Step by Step
We know that
$\Delta G=\Sigma n\Delta G_f(products)-\Sigma n\Delta G_f(reactants)$
We plug in the known values to obtain:
$\Delta G=(-16.40+124.7)-(-50.80)$
$\Delta G=159.10 kJ/mol$
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