General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 18 - Thermodynamics and Equilibrium - Questions and Problems - Page 773: 18.72

Answer

$88.44\frac{J}{K.mol}$

Work Step by Step

We know that $\Delta S=\frac{\Delta H_{vap}}{T}$ We plug in the known values to obtain: $\Delta S=\frac{29100}{329}=88.44\frac{J}{K.mol}$
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