General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 1 - Chemistry and Measurement - Questions and Problems - Page 38: 1.150

Answer

a - Speed in miles per hour =39.6 $\frac{mi}{hour}$. b - Speed in km per hour = 63.75 $\frac{km}{hour}$. c - Gas mileage in km per liter =11.4 $\frac{km}{L}$.

Work Step by Step

Speed is calculated: speed = $\frac{distance}{time}$ a - Speed in miles per hour = $\frac{distance (miles)}{time(hours)}$ Speed in miles per hour = $\frac{832(miles)}{21(hours)}$ Speed in miles per hour =39.6 $\frac{mi}{hour}$ b - Speed in km per hour = $\frac{distance (km)}{time(hours)}$ First we convert miles into km, knowing that 1 mi = 1.609 km. 832 mi = 832 mi x $\frac{1.609 km}{1 mi}$ 832 mi = 1,338.7 km Speed in km per hour = $\frac{1,338.7(km)}{21(hours)}$ Speed in km per hour = 63.75 $\frac{km}{hour}$ c - Gas mileage in km per liter = $\frac{distance (km)}{volume(L)}$ First we convert the volume from gal to L knowing that 1 gal = 3.79 L. 31 gal = 31 gal x $\frac{3.79 (L)}{1 (gal)}$ 31 gal = 117.4 L Gas mileage in km per liter = $\frac{distance (km)}{volume(L)}$ Gas mileage in km per liter = $\frac{1,338.7(km)}{117.4(L)}$ Gas mileage in km per liter =11.4 $\frac{km}{L}$
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