General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 1 - Chemistry and Measurement - Questions and Problems - Page 38: 1.133

Answer

a. 8.45 kg = 8.45 x $10^{9}$ $\mu$g b. 318 mikroseconds= 3.18 x $10^{-1}$ millisecond c.93 km = 9.3 x $10^{13}$ nm d. 37.1 mm = 3.71 cm

Work Step by Step

a. 8.45 kg to micrograms 8.45 kg = 8.45 x $10^{3}$ $\frac{g}{kg}$ = 8.45 x $10^{3}$ g 8.45 kg = 8.45 x $10^{3}$ g x $10^{6}$ $\mu$g/g 8.45 kg = 8.45 x $10^{9}$ $\mu$g b. 318 mikroseconds to milliseconds 318 mikroseconds = 318 mikroseconds x $10^{-6}$ second/ mikrosecond 318 mikroseconds = 318 x $10^{-6}$ seconds 318 mikroseconds= 318 x $10^{-6}$ seconds x $10^{3}$ millisecond/second 318 mikroseconds= 318 x $10^{-3}$ millisecond 318 mikroseconds= 3.18 x $10^{-1}$ millisecond C. 93 km to nanometers 93 km = 93 km x $10^{3}$ m/km 93 km = 93 x $10^{3}$ m 93 x $10^{3}$ m = 93 x $10^{3}$ m x $10^{9}$nm / m 93 x $10^{3}$ m = 93 x $10^{12}$ nm So, 93 km = 93 x $10^{12}$ nm or 93 km = 9.3 x $10^{13}$ nm d. 37.1 mm to centimeter We know 1 m = $10^{2}$ cm 1 m = $10^{3}$ mm So 1 cm = 10 mm or 1mm = $10^{-1}$ cm Than 37.1 mm = 37.1 x $10^{-1}$ cm 37.1 mm = 3.71 cm
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