Answer
m (of carbon dioxide) = 0.22 g
Work Step by Step
1- Apply the law of conservation of mass for this chemical reaction:
m (of calcium carbonate) + m (of acid solution) = m (of carbon dioxide ) + m (of solution)
2- Step two: Replace the known masses of :
0.853 g + 56.519 g = m (of carbon dioxide) + 57.152 g
3- Step three: find the mass of carbon dioxide that was produced in this chemical reaction
57.3722 g = m (of carbon dioxide) + 57.152 g
57.3722 g- 57.152 g = m (of carbon dioxide)
m (of carbon dioxide) = 0.22 g
