Answer
These samples are not a compound of iron and oxygen.
Work Step by Step
Strategy: For these samples of oxygen and iron to represent the same compound, the mass percentage of iron and/or mass percentage of oxygen in each sample, should be equal or similar (within experimental error).
Therefore, we have to calculate the mass percentage of iron and /or oxygen for each of the samples:
Sample A : mass percentage iron = $\frac{Iron ( mass)}{Sample A (mass)}\times100$ = $\frac{1.094 g}{1.518 g}\times100$ = 72.07%
Sample B : mass percentage iron = $\frac{Iron ( mass)}{Sample A (mass)}\times100$ = $\frac{1.449 g}{2.056 g}\times100$ = 70.48%
Sample C : mass percentage iron = $\frac{Iron ( mass)}{Sample A (mass)}\times100$ = $\frac{1.335 g}{1.873 g}\times100$ = 71.28%
Mass percentage of iron is different in samples A, B, and C, therefore these samples are not a compound of iron and oxygen.
