Answer
$$\begin{vmatrix}
Compound& [ PCl_5 ]& [ PCl_3 ]& [ Cl_2 ]\\
Initial& 0.075 & 0 & 0 \\
Change& -x& +x& +x\\
Equilibrium& 0.075 -x& 0 +x& 0 +x\\
\end{vmatrix}$$
Work Step by Step
1. Calculate the concentration of $PCl_5$:
$$Molarity = \frac{0.15 \space mol}{2.0 \space L} = 0.075 \space M$$
2. Draw the ICE table for this equilibrium:
$$\begin{vmatrix}
Compound& [ PCl_5 ]& [ PCl_3 ]& [ Cl_2 ]\\
Initial& 0.075 & 0 & 0 \\
Change& -x& +x& +x\\
Equilibrium& 0.075 -x& 0 +x& 0 +x\\
\end{vmatrix}$$
