Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 4 - Reactions in Aqueous Solution - Exercises: 4.69b

Answer

30mL of 0.15M K2CrO4 has more K+ ions

Work Step by Step

The first solution is 30mL of 0.15M K2CrO4. First off, we find how many moles of K2CrO4 we have as follows: 30mL * ( 1L/1000mL) = 0.030 L 0.15M = 0.15mol/L * (0.030L) = 0.0045 mol K2CrO4 Then we see that in K2CrO4 there are 2 moles of K+ for each mole of K2CrO4 so 0.0045 mol K2CrO4 * (2 mol K+/1 mol K2CrO4) = 0.009 mole K+ The second solution is 25mL of 0.080 M K3PO4 Here again 25mL --> 0.025L 0.080 mol/L * 0.025L = 0.002 mole K3PO4 Last, there are 3 moles of K+ for each mole of K3PO4 so we have 0.002 mole K3PO4 * (3 moles K+/1mole K3PO4) = 0.006 moles K+ Since 0.009 > 0.006 then solution 1 has more
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.