Answer
$KI$ $0.25M$ has a higher concentration of $ I^-$.
Work Step by Step
$BaI_2$ $0.10M:$
$[I^-] = 2 \times [BaI_2]$
$[I^-] = 0.20M$
$KI$ $0.25M:$
$[I^-] = 1 \times [KI]$
$[I^-] = 0.25M$
Chemistry: The Central Science (13th Edition)
by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.
Published by
Prentice Hall
ISBN 10:
0321910419
ISBN 13:
978-0-32191-041-7
Chapter 4 - Reactions in Aqueous Solution - Exercises - Page 160: 4.70a
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