Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises: 3.61c

Answer

0.61 grams

Work Step by Step

For each mole of Na2SiO3, you need 8 moles of HF. Therefore, if we have 0.800g of HF then we need to convert this to moles. H is 1 g/mol F is 19 g/mol 20 g/mol. Then we have 0.8g * (1 mole/20g) = 0.04 moles HF We need 8 moles HF for every mole of Na2SiO3 so 0.04/8 = 0.005 moles Na2SiO3. The molar mass of Na2SiO3 is: Na is 23, 23*2 = 46 Si is 28 O is 16, 3*16 = 48 46+28+48 = 122 g/mol 0.005 moles * 122g/mol = 0.61 grams
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.