Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises: 3.64a

Answer

Fe2O3 + 3CO --> 2Fe + 3CO2

Work Step by Step

Fe2O3 + CO --> Fe + CO2 First we balance the Fe since it appears only once on each side. There are 2 on the left and only one on the right so we multiply the right by 2 Fe2O3 + CO --> 2Fe +CO2 Next we balance the Cs and we have 1 on the left and 1 on the right. Next we balance the Os and we have 4 on the left and 2 on the right so we need to multiply the CO2 by 2 on the right. Fe2O3 + CO --> 2Fe + 2CO2 Now the Os are balanced but the Cs are not. We multiply the CO by 2 Fe2O3 + 2CO --> 2Fe +2CO2 Now we have 5 Os on the left and only 4 on the right so we add one to the left to get an even number by adding another CO. Fe2O3 + 3CO --> 2Fe + 2CO2 Now we need another C on the right Fe2O3 + 3CO --> 2Fe + 3CO2 Now the Os are balanced with 6 on the left and 6 on the right
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