Answer
Approximately 0.012 mol/L.
Work Step by Step
1. Find the pOH of the solution.
pH + pOH = 14
12.08 + pOH = 14
pOH = 1.92
2. Now, find the concentration of $O^{}H^{-}$ in the solution.
$[O^{}H^{-}]$ = $10^{-pOH}$
$[O^{}H^{-}]$ = $10^{-1.92}$
$[O^{}H^{-}]$ $\approx$ 0.012
3. Because we have 1 OH in 1 KOH, we can assume that the concentration of KOH is about 0.012 mol/L.
