Answer
The final pressure is equal to 4.26 atm.
Work Step by Step
1. The temperatures used in gas law calculations must be converted to Kelvin values.
$C^o + 273 = K$
$25 + 273 = K$
$K = 298$
Therefore: $T_1 = 298 \space K$
- Convert the final volume to "L":
$1850 \space mL \times \frac{1 \space L}{1000 \space mL} = 1.85 \space L$
2. Write the combined gas law, and rearrange it to solve for $P_2$, which is the final pressure.
$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$
- Divide both sides by $V_2$:
$\frac{P_1V_1}{T_1V_2} = \frac{P_2}{T_2}$
- Multiply both sides by $T_2$:
$\frac{P_1V_1T_2}{T_1V_2} = P_2$
3. Substitute the values and find the $T_2$ value:
$\frac{845 \space mmHg \times 6.50 \space L \times 325 \space K}{298 \space K \times 1.85 \space L } = P_2$
$T_2 = 3240 \space mmHg$
4. Convert the final pressure to atmospheres:
$3240 \space mmHg \times \frac{1 \space atm}{760 \space mmHg} = 4.26 \space atm$
$P_2 = 4.26 \space atm$
