Answer
The final volume of the gas is equal to 38.4 mL.
Work Step by Step
1. The temperatures used in gas law calculations must be converted to Kelvin values.
$C^o + 273 = K$
$112 + 273 = K$
$K = 385$
Therefore: $T_1 = 385 \space K$
$C^o + 273 = K$
$(-15) + 273 = K$
$K = 258 $
Therefore: $T_2 = 258 \space K$
2. Write the combined gas law, and rearrange it to solve for $V_2$, which is the final volume.
$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$
- Divide both sides by $P_2$:
$\frac{P_1V_1}{T_1P_2} = \frac{V_2}{T_2}$
- Multiply both sides by $T_2$:
$\frac{P_1V_1T_2}{T_1P_2} = V_2$
3. Substitute the values and find the $V_2$ value:
$\frac{1.20 \space atm \times 735 \space mL \times 258 \space K}{385 \space K \times 15.4 \space atm } = V_2$
$V_2 = 38.4 \space mL$
