Answer
0.83 atm
Work Step by Step
Let $T1=75^{o}C+273K=348K$, P1=1.20 atm,
P2=? $T2=-32^{o}C+273=241K$,
Using Gay Lussac's Law, we have:
$\frac{P1}{T1}= \frac{P2}{T2}$
$\frac{1.20}{348} = \frac{P2}{241}$
P2 = 0.83 atm
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