Answer
1.51 atm
Work Step by Step
Let $T_{1} = 12^{o}C + 273 K = 285 K$, $P_{1} = 1.4 atm$,
$P_{2} = ?$ $T_{2} = 35^{o}C + 273 = 308 K$,
Using Gay Lussac's Law, we have:
$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$
$\frac{1.4 atm}{285 K} = \frac{P_{2}}{308 K}$
$P_{2} = \frac{308 K}{285 K}$ x 1.4 atm
= 1.51 atm