Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 2 - Section 2.7 - Density - Challenge Questions - Page 54: 2.98b

Answer

$$3.83 \space g$$

Work Step by Step

As we have calculated in the last exercise (2.98a), the mass of the necklace is equal to 42.5 g. $$100 \% \space necklace = 9.0 \% \space copper$$ $$42.5 \space g(necklace) \times \frac{9.0 \% \space copper}{100 \% \space necklace} = 3.83 \space g(copper)$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.