Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 4 - Reactions in Aqueous Solutions - Questions & Problems: 4.64

Answer

Please see the work below.

Work Step by Step

We know that $Moles=Volume\times Molarity$ We plug in the known values to obtain: $5.5\times 0.035=0.1925 \space moles$ $Molar \space mass\space of KOH=56$ and $Mass=moles\times Molar\space mass$ We plug in the known values to obtain: $Mass=0.1925\times 56=10.78g$
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