Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 4 - Reactions in Aqueous Solutions - Questions & Problems - Page 161: 4.46

Answer

Please see the work below.

Work Step by Step

The oxidation number of hydrogen in all cases except in hydrides is +1. The oxidation number of oxygen in all cases except in peroxides and superoxides is -2. Thus in below oxoacids of phosphorus oxidation number of ‘P’ is may not the same. We can arbitrarily take it as ‘x’. a) $HPO_{3}$ $1 + x +(3\times -2) = 0$ Then x = +5 Hence oxidation number of Phsphorus in $HPO_{3}$ = +5 b) $H_{3}PO_{2}$ $(3\times 1) + x +(2\times-2) = 0$ Then x = +1 Hence oxidation number of Phsphorus in $H_{3}PO_{2}$ = +1 c) $H_{3}PO_{3}$ $(3\times 1) + x +(3\times-2) = 0$ Then x = +3 Hence oxidation number of Phsphorus in $H_{3}PO_{3}$ = +3 d) $H_{3}PO_{4}$ $(3\times 1) + x +(4\times-2) = 0$ Then x = +5 Hence oxidation number of Phsphorus in $H_{3}PO_{4}$ = +5 e) $H_{4}P_{2}O_{7}$ $(4\times 1) +(2 \times x) +(7 \times-2) = 0$ Then x = +5 Hence oxidation number of Phsphorus in $H_{4}P_{2}O_{7}$ = +5 f) $H_{5}P_{3}O_{10}$ $(5\times 1) +(3\times x) +(10\times-2) = 0$ Then x = +5 Hence oxidation number of Phsphorus in $H_{5}P_{3}O_{10}$ = +5
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.