Answer
a. $NH_{4}NO_{3}$ -> $N_{2}O+2H_{2}O$
b. $20g$ $N_{2}O$
Work Step by Step
a. $NH_{4}NO_{3}$ -> $N_{2}O+2H_{2}O$
b. mass of $N_{2}O$ = $\frac{(0.46molNH_{4}NO_{3})\times(1molN_{2}O)\times(44.02gN_{2}O)}{(1molNH_{4}NO_{3})\times(1molN_{2}O)}$
$=20g$ $N_{2}O$
