Answer
$255.9g$ ethanol
volume = $0.324L$
Work Step by Step
$C_{6}H_{12}O_{6}$ -> $2C_{2}H_{5}OH+2CO_{2}$
Mass of ethanol = $\frac{(500.4gGlucose)\times(1molGlucose)\times(2molEthanol)\times(46.0684gEthanol)}{(180.1548gGlucose)\times(1molEthanol)\times(1molEthanol)}$
=255.96g g
volume = $\frac{255.96g}{0.789g/L}$
=324.41mL
=0.324L
